Integrand size = 35, antiderivative size = 156 \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=-\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}+\frac {a \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {b \sqrt {c} \sqrt {a^2+2 a b x+b^2 x^2} \text {arctanh}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a+b x} \]
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Time = 0.07 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.229, Rules used = {1015, 827, 858, 223, 212, 272, 65, 214} \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\frac {a \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {b \sqrt {c} \sqrt {a^2+2 a b x+b^2 x^2} \text {arctanh}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a+b x}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} (a-b x) \sqrt {c+d x^2}}{x (a+b x)} \]
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Rule 65
Rule 212
Rule 214
Rule 223
Rule 272
Rule 827
Rule 858
Rule 1015
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {\left (2 a b+2 b^2 x\right ) \sqrt {c+d x^2}}{x^2} \, dx}{2 a b+2 b^2 x} \\ & = -\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {-4 b^2 c-4 a b d x}{x \sqrt {c+d x^2}} \, dx}{2 \left (2 a b+2 b^2 x\right )} \\ & = -\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}+\frac {\left (2 b^2 c \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {1}{x \sqrt {c+d x^2}} \, dx}{2 a b+2 b^2 x}+\frac {\left (2 a b d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {1}{\sqrt {c+d x^2}} \, dx}{2 a b+2 b^2 x} \\ & = -\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}+\frac {\left (b^2 c \sqrt {a^2+2 a b x+b^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {c+d x}} \, dx,x,x^2\right )}{2 a b+2 b^2 x}+\frac {\left (2 a b d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{2 a b+2 b^2 x} \\ & = -\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}+\frac {a \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}+\frac {\left (2 b^2 c \sqrt {a^2+2 a b x+b^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{-\frac {c}{d}+\frac {x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{d \left (2 a b+2 b^2 x\right )} \\ & = -\frac {(a-b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x (a+b x)}+\frac {a \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {b \sqrt {c} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a+b x} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.70 \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\frac {\sqrt {(a+b x)^2} \left ((-a+b x) \sqrt {c+d x^2}+2 b \sqrt {c} x \text {arctanh}\left (\frac {\sqrt {d} x-\sqrt {c+d x^2}}{\sqrt {c}}\right )-a \sqrt {d} x \log \left (-\sqrt {d} x+\sqrt {c+d x^2}\right )\right )}{x (a+b x)} \]
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Time = 0.50 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.72
method | result | size |
risch | \(-\frac {a \sqrt {d \,x^{2}+c}\, \sqrt {\left (b x +a \right )^{2}}}{x \left (b x +a \right )}+\frac {\left (a \sqrt {d}\, \ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right )+\sqrt {d \,x^{2}+c}\, b -b \sqrt {c}\, \ln \left (\frac {2 c +2 \sqrt {c}\, \sqrt {d \,x^{2}+c}}{x}\right )\right ) \sqrt {\left (b x +a \right )^{2}}}{b x +a}\) | \(112\) |
default | \(-\frac {\operatorname {csgn}\left (b x +a \right ) \left (-a \,d^{\frac {3}{2}} x^{2} \sqrt {d \,x^{2}+c}+c^{\frac {3}{2}} \ln \left (\frac {2 c +2 \sqrt {c}\, \sqrt {d \,x^{2}+c}}{x}\right ) \sqrt {d}\, b x +a \left (d \,x^{2}+c \right )^{\frac {3}{2}} \sqrt {d}-\sqrt {d \,x^{2}+c}\, \sqrt {d}\, b c x -\ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right ) a c d x \right )}{c x \sqrt {d}}\) | \(120\) |
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Time = 0.29 (sec) , antiderivative size = 333, normalized size of antiderivative = 2.13 \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\left [\frac {a \sqrt {d} x \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + b \sqrt {c} x \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) + 2 \, \sqrt {d x^{2} + c} {\left (b x - a\right )}}{2 \, x}, -\frac {2 \, a \sqrt {-d} x \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - b \sqrt {c} x \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) - 2 \, \sqrt {d x^{2} + c} {\left (b x - a\right )}}{2 \, x}, \frac {2 \, b \sqrt {-c} x \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) + a \sqrt {d} x \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + 2 \, \sqrt {d x^{2} + c} {\left (b x - a\right )}}{2 \, x}, -\frac {a \sqrt {-d} x \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - b \sqrt {-c} x \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) - \sqrt {d x^{2} + c} {\left (b x - a\right )}}{x}\right ] \]
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\[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\int \frac {\sqrt {c + d x^{2}} \sqrt {\left (a + b x\right )^{2}}}{x^{2}}\, dx \]
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\[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\int { \frac {\sqrt {d x^{2} + c} \sqrt {{\left (b x + a\right )}^{2}}}{x^{2}} \,d x } \]
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Time = 0.29 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.81 \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\frac {2 \, b c \arctan \left (-\frac {\sqrt {d} x - \sqrt {d x^{2} + c}}{\sqrt {-c}}\right ) \mathrm {sgn}\left (b x + a\right )}{\sqrt {-c}} - a \sqrt {d} \log \left ({\left | -\sqrt {d} x + \sqrt {d x^{2} + c} \right |}\right ) \mathrm {sgn}\left (b x + a\right ) + \sqrt {d x^{2} + c} b \mathrm {sgn}\left (b x + a\right ) + \frac {2 \, a c \sqrt {d} \mathrm {sgn}\left (b x + a\right )}{{\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} - c} \]
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Timed out. \[ \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^2} \, dx=\int \frac {\sqrt {{\left (a+b\,x\right )}^2}\,\sqrt {d\,x^2+c}}{x^2} \,d x \]
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